3c^2=240

Solution for 3c^2=240 equation:

3c^2=240

We move all terms to the left:

3c^2-(240)=0

a = 3; b = 0; c = -240;
Δ = b2-4ac
Δ = 02-4·3·(-240)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*3}=\frac{0-24\sqrt{5}}{6}
=-\frac{24\sqrt{5}}{6}
=-4\sqrt{5}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*3}=\frac{0+24\sqrt{5}}{6}
=\frac{24\sqrt{5}}{6}
=4\sqrt{5}
$